Assignment 4 - Control Theory 2

Second Half 2003

Problem 1

Let G(s) be the plant transfer function. The closed-loop transfer function is
T(s) =  G(s)

1+G(s)
.
Let wp be such that |G(jwp)| = 1 and ÐG(jwp) = f, then prove that
|T(jwp)| =  1

2sin  fm

2
where phase margin fm = 180 + f,      -180° £ f £ 180°.

Problem 2

Let
C(s) =  1+s/wz

1+s/wp
;       wp > wz
and wl be the frequency at which ÐC(jwl) is maximum over all w > 0. Show that
wl =
Ö
 

wz wp
 
,

fl D
=
 
ÐC(jwl) = sin-1 æ
è
 wp/wz - 1

wp/wz + 1
ö
ø
, and

20log10|C(jwl)| = 10log10(wp/wz).
The ratio wp/wz is often expressed as m. Make a table of a few important values of m and fl.

Problem 3

feedbackunity.gif
Figure 1: Block Diagram: Problem 3
Let the true system transfer function in the above Figure 1 be modelled using a multiplicative uncertainty as [G\tilde](s) = G(s)(1 + L(s)). The model we have available for design is G(s) and let the uncertainty magnitude be, lm(jw) = |L(jw)|. The closed-loop system sensitivity function is such that
ê
ê
 1

1+tildeG(jw)
ê
ê
<  1

pm(j w)
.
Prove that for a stable feedback system to satisfy the sensitivity function constraint the following inequality should be satisfied:
ê
ê
 G(jw)

1+G(jw)
ê
ê
lm(jw) + ê
ê
 1

1+G(jw)
ê
ê
pm(jw) < 1.

Problem 4

feedback.gif
Figure 2: Block Diagram: Problem 4
In the above Figure 2, let
G(s) =  100

(s/10+1)(s/20+1)
.
Design controller C(s) such that,
  1. The closed-loop system has zero steady-state error to unit step reference input;

  2. The crossover frequency is above 500 rad/s;

  3. There is a minimum 60° phase margin.

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On 08 Aug 2003, 16:46.